2x^2-4x=173

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Solution for 2x^2-4x=173 equation:



2x^2-4x=173
We move all terms to the left:
2x^2-4x-(173)=0
a = 2; b = -4; c = -173;
Δ = b2-4ac
Δ = -42-4·2·(-173)
Δ = 1400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1400}=\sqrt{100*14}=\sqrt{100}*\sqrt{14}=10\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-10\sqrt{14}}{2*2}=\frac{4-10\sqrt{14}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+10\sqrt{14}}{2*2}=\frac{4+10\sqrt{14}}{4} $

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